统计数字出现次数 给你一组数字 统计每个数字的出现次数 次数=数字大小的 认作是完美数字 统计有几个完美数字 例如 【1,2,2,3,3,3】 有6个完美数字
好的,我可以帮你统计数字出现的次数并计算完美数字的个数。你可以将数字列表输入给我,然后我会进行处理。
以下是一个示例代码,用于统计数字出现的次数并计算完美数字的个数:
```python
def count_occurrences(numbers):
occurrences = {}
perfect_count = 0
for num in numbers:
if num in occurrences:
occurrences[num] += 1
else:
occurrences[num] = 1
for count in occurrences.values():
if count == num:
perfect_count += 1
return perfect_count
numbers = [1, 2, 2, 3, 3, 3]
perfect_count = count_occurrences(numbers)
print("完美数字的个数:", perfect_count)
```
你可以将你的数字列表替换掉`numbers`变量,然后运行代码即可得到完美数字的个数。希望对你有帮助!如果有任何问题,请随时提问。
以下是一个示例代码,用于统计数字出现的次数并计算完美数字的个数:
```python
def count_occurrences(numbers):
occurrences = {}
perfect_count = 0
for num in numbers:
if num in occurrences:
occurrences[num] += 1
else:
occurrences[num] = 1
for count in occurrences.values():
if count == num:
perfect_count += 1
return perfect_count
numbers = [1, 2, 2, 3, 3, 3]
perfect_count = count_occurrences(numbers)
print("完美数字的个数:", perfect_count)
```
你可以将你的数字列表替换掉`numbers`变量,然后运行代码即可得到完美数字的个数。希望对你有帮助!如果有任何问题,请随时提问。